Meriam, Kraige & Bolton — Analysis of Structures: Problem 6_49

⚡ Mecademy AIENG정역학 · ch6  Problem Statement Calculate the rightward force which would remove the wedge from under the door of Prob. 6/48. Assume that corner does not slip for your calculation of , but then check this assumption; the coefficient of static friction at is . Data from Prob. 6/48: The 100-kg industrial door with mass center at is being positioned for repair by insertion of the wedge under corner . Horizontal movement is prevented by the small ledge at corner . If the coefficients of static friction at both the top and bottom wedge surfaces are , determine the force required to lift the door at . The horizontal distance from to is , and from to corner is . Problem 6/49 (a) Determination of Vertical Reaction at B ● Calculation Process 1. Present Final Formula: Considering the door as a rigid body in equilibrium, the sum of moments about point must be zero to determine the vertical component of the reaction at . 2. Substitute Values: Weight of the door: Horizontal distance Horizontal distance 3. Partial Operations: P ′ AP ′ A0.60 G 5 ∘ B A 0.60PB AG1.2 mGB1 m A B M = ∑ A 0⇒R (L )− ByAB W(L )= AG 0 W=m⋅g=100 kg⋅ 9.81 m/s= 2 981 N L = AB 1.2 m+1 m=2.2 m L = AG 1.2 m R (2.2 m)− By (981 N)(1.2 m)=0 2.2R = By 1177.2 4. Final Calculation: ● Final Conclusion: The vertical component of the force exerted by the wedge on the door at corner is . (b) Calculation of Force required to remove the wedge ● Calculation Process 1. Present Final Formula: For the wedge to be removed ri