Meriam, Kraige & Bolton — Analysis of Structures: Problem 6_2

⚡ Mecademy AIENG정역학 · ch6  Problem Statement The 700-N force is applied to the 100-kg block, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the block. Problem 6/2 (a) Magnitude and Direction of the Friction Force 1. Present Final Formula: First, determine the normal force from vertical equilibrium: Second, determine the horizontal component of the applied force: Third, determine the maximum possible static friction force: If , slipping occurs and the actual friction force is kinetic: 2. Substitute Values: 3. Partial Operations: Calculate Normal Force: Calculate horizontal applied force: Calculate max static friction: Determine state of motion: Since , the block will slip. NF =∑ y N+ Psinθ−mg=0⇒N=mg−Psinθ P = x Pcosθ F = s,max μ N s P > x F s,max F= F = k μ N k N= (100 kg)(9.81 m/s)− 2 (700 N)sin30 ∘ P = x (700 N)cos30 ∘ F = s,max (0.80)N F = k (0.60)N N=981−350=631 N P = x 700⋅0.8660=606.22 N F = s,max 0.80⋅631=504.8 N P = x 606.22 N>F = s,max 504.8 N 4. Final Calculation: Friction force Direction: Since the force is directed to the right, the friction force acts to the left. ● Final Conclusion: The magnitude of the friction force is and it is directed to the left. ✨ Final Answer Summary (a) to the left Mecademy AI Solution · ENGProblem 6/2 F=F = k μ N= k 0.60⋅631=378.6 N P x F 378.6 N 378.6 N