Engineering Mechanics: Statics 9th Edition · Distributed Forces: Centroids and Centers of Gravity · Problem 5_118
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Meriam, Kraige & Bolton — Distributed Forces: Centroids and Centers of Gravity: Problem 5_118
⚡ Mecademy AIENG정역학 · ch5 Problem Statement Plot the shear and moment diagrams for the beam loaded as shown. What are the values of the shear force and bending moment at B? Determine the distance b to the right of A where the bending moment equals zero for the first time. Problem 5/118 (a) Support Reactions at A and B ● Calculation Process 1. Equilibrium Equations: To find the reactions and , we apply the moment equilibrium about point and the force equilibrium in the vertical direction. Let the left end of the beam be at . Point load is at . Support is at . Support is at . Triangular distributed load starts at and ends at . Its resultant is acting at its centroid . Counter-clockwise couple acts at . 2. Moment Equilibrium about A (): (Note: Distances are relative to . Forces to the left of or causing CCW rotation are positive in this sum). Self-Correction: Let's re-verify the moment arm for the triangular load. It is at , and is at . The arm is . Correct. Let's re-check the signs. Taking about : R A R B A x=0 7 kNx=2 m Ax=5 m Bx=10 m x=12 mx=15 m F = D × 2 1 3×4=6 kNx = D 12+ (3)= 3 2 14 m M = C 30 kN⋅mx=15 m M =∑ A 0 (7 kN)(3 m)−R (5 m)+ B (6 kN)(9 m)−30 kN⋅m=0 AA 21−5R + B 54−30=0 5R = B 45⟹R = B 9 kN x=14 Ax=514−5=9 m ↺+A at left: at right: (assuming up) at right: Couple at right end: (upwards). 3. Force Equilibrium (): ● Final Conclusion: The reaction at support is (upward) and at support is (upward). (b) Shear Force and Bending Moment at B ● Calculation Process 1. Shea
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주어진 조건: 2 m, 5 m, 10 m, 15 m, 14 m, 30 kN
구하는 것: (a) Support Reactions at A and B ● Calculation Process 1; (b) Shear Force and Bending Moment at B ● Calculation Process 1
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Engineering Mechanics: Statics · 9th Edition
저자: Meriam, Kraige & Bolton
출판사: Wiley
단원: Distributed Forces: Centroids and Centers of Gravity