Meriam, Kraige & Bolton — Equilibrium of Rigid Bodies: Problem 4_104

⚡ Mecademy AIENG정역학 · ch4  Problem Statement The elements of a rear suspension for a front-wheel-drive car are shown in the figure. Determine the magnitude of the force at each joint if the normal force exerted on the tire has a magnitude of . Problem 4/104 (a) Magnitude of force at each joint ● Calculation Process 1. Equilibrium Analysis of the Wheel Assembly (Hub): The wheel hub is a rigid body connected at joints and . Link is a two-force member, so it exerts a horizontal force at joint . The tire force acts vertically at the ground contact patch. Let the vertical joint separation be and the tire offset be . Sum of moments about joint : Forces at joints and : Since is a two-force member, the force magnitude at both joints is . Force at joint from the hub FBD: 2. Equilibrium Analysis of the Arm : The arm is pinned to the frame at , the shock at , and the hub at . Let the horizontal positions relative to be and . The shock is a two-force member pinned at and relative F 3600 N BCBE F BE BF=3600 N h= 60 mmd=165 mm C M = ∑ C 0⟹F ⋅ BE h−F⋅d=0 F = BE = h F⋅d = 60 3600⋅165 9900 N BEBE F = B F = E 9.90 kN C F = ∑ x 0⟹C − x F = BE 0⟹C = x 9900 N F = ∑ y 0⟹C + y F=0⟹C = y −3600 N F = C = C +C x 2 y 2 = 9900+(−3600) 22 10534 N AC ACADC Ax = D 170 mmx = C 260 mm DFD(170,60)F(220,190) to . The direction vector is with length . Sum of moments about joint for the arm: Note: on the arm, and . Forces at joints and : Magnitude is . Reaction at joint : ● Final Conclusion: The magnitudes of t