Engineering Mechanics: Statics 9th Edition · Statics of Particles · Problem 2_66
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Meriam, Kraige & Bolton — Statics of Particles: Problem 2_66
⚡ Mecademy AIENG정역학 · ch2 Problem Statement 2/66 The device shown is a part of an automobile seat-back-release mechanism. The part is subjected to the 4-N force exerted at A and a 300-N · mm restoring moment exerted by a hidden torsional spring. Determine the y-intercept of the line of action of the single equivalent force. Problem 2/66 ● Calculation of the Resultant Force Components The system is subjected to a single external force acting at point . The direction of this force is above the horizontal. The single equivalent force for the system is equal to this force . 1. Present Final Formula: 2. Substitute Values: 3. Final Calculation: Thus, the resultant force is . ● Calculation of the Resultant Moment about the Origin The total moment about the origin is the sum of the moment created by force acting at and the applied restoring couple . Based on the diagram and the term "restoring," the spring moment is counter-clockwise (CCW), while the moment of force is clockwise (CW). F=4 NA 15 ∘ R F R = x Fcosθ,R = y Fsinθ R = x 4cos(15) ∘ R = y 4sin(15) ∘ R = x 4×0.9659=3.8637 N R = y 4×0.2588=1.0353 N R=3.8637i+1.0353j N O OF A(10,40) mmM=300 N⋅ mm F 1. Present Final Formula: 2. Substitute Values: Using CCW as positive: 3. Partial Operations: 4. Final Calculation: ● Determination of the y-intercept of the Line of Action The line of action of the single equivalent force must produce the same resultant moment about the origin. The equation for the line of action is . The y- interc
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주어진 조건: 3.8637 N, 1.0353 N, 1.0353j, 300 N
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Engineering Mechanics: Statics · 9th Edition
저자: Meriam, Kraige & Bolton
출판사: Wiley
단원: Statics of Particles