Principles of Physics 11th ISV Edition · Gauss' Law · Problem 52
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Walker, Halliday & Resnick — Gauss' Law: Problem 52
52 When a shower is turned on in a closed bathroom, the splashing of the water on the bare tub can fill the room’s air with negatively charged ions and produce an electric field in the air as great as 1000 N/C. Consider a bathroom with dimensions 2.5 m x 3.0 m x 2.0 m. Along the ceiling, floor, and four walls, approximate the electric field in the air as being directed perpendicular to the surface and as having a uniform magnitude of 500 N/C. Also, treat those surfaces as forming a closed Gaussian surface around the room’s air. What are (a) the volume charge density \(\rho\) and (b) the number of excess elementary charges \(e\) per cubic meter in the room’s air?
📝 풀이 접근법
주어진 조건: 1000 N, 2.5 m, 3.0 m, 2.0 m, 500 N
구하는 것: (a) the volume charge density \; (b) the number of excess elementary charges \
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Principles of Physics · 11th ISV Edition
저자: Walker, Halliday & Resnick
출판사: Wiley
단원: Gauss' Law