Physics for Scientists and Engineers 10th Edition · Heat Engines, Entropy, and the Second Law of Thermodynamics · Problem 10
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Serway & Jewett — Heat Engines, Entropy, and the Second Law of Thermodynamics: Problem 10
An ideal refrigerator or ideal heat pump is equivalent to a Carnot engine running in reverse. That is, energy \(|Q_c|\) is taken in from a cold reservoir and energy \(|Q_h|\) is rejected to a hot reservoir. (a) Show that the work that must be supplied to run the refrigerator or heat pump is \[W = \frac{T_h - T_c}{T_c} |Q_c|\] (b) Show that the coefficient of performance (COP) of the ideal refrigerator is \[\text{COP} = \frac{T_c}{T_h - T_c}\]
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구하는 것: (a) Show that the work that must be supplied to run the refriger; (b) Show that the coefficient of performance
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Physics for Scientists and Engineers · 10th Edition
저자: Serway & Jewett
출판사: Cengage
단원: Heat Engines, Entropy, and the Second Law of Thermodynamics