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Physics for Scientists and Engineers 10th Edition · Oscillatory Motion · Problem 48
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Serway & Jewett — Oscillatory Motion: Problem 48

A smaller disk of radius \(r\) and mass \(m\) is attached rigidly to the face of a second larger disk of radius \(R\) and mass \(M\) as shown in Figure P15.48. The center of the small disk is located at the edge of the large disk. The large disk is mounted at its center on a frictionless axle. The assembly is rotated through a small angle \(\theta\) from its equilibrium position and released. (a) Show that the speed of the center of the small disk as it passes through the equilibrium position is \(v = 2 \left[ \frac{Rg(1 - \cos \theta)}{(M/m) + (r/R)^2 + 2} \right]^{1/2}\). (b) Show that the period of the motion is \(T = 2\pi \left[ \frac{(M + 2m)R^2 + mr^2}{2mgR} \right]^{1/2}\).

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주어진 조건: 2m

구하는 것: (a) Show that the speed of the center of the small disk as it pa; (b) Show that the period of the motion is \

이 문제는 Oscillatory Motion 단원의 핵심 개념을 다룹니다. Physics for Scientists and Engineers 10th Edition의 체계적인 풀이 과정을 통해 단계별 분석과 공식 적용을 통해 정답을 도출합니다. 전체 풀이는 솔루션 패스로 확인하세요.

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📘 교재 정보

Physics for Scientists and Engineers · 10th Edition
저자: Serway & Jewett
출판사: Cengage
단원: Oscillatory Motion