Randall D. Knight — Kinematics in Two Dimensions: Problem Exercise_9

A particle’s trajectory is described by \( x = (\frac{1}{6}t^{3} - t^{2}) \text{ m} \) and \( y = (\frac{1}{6}t^{2} - t) \text{ m} \), where \( t \) is in s. a. What are the particle’s position and speed at \( t = 0 \text{ s} \) and \( t = 6 \text{ s} \)? b. What is the particle’s direction of motion, measured as an angle from the x-axis, at \( t = 0 \text{ s} \) and \( t = 6 \text{ s} \)?