Randall D. Knight — Impulse and Momentum: Problem 61

A 900 g particle has velocity \(v_x = -20 \text{ m/s}\) at \(t = -4 \text{ s}\). Force \(F_x = (16 - t^2) \text{ N}\), where \(t\) is in s, is exerted on the particle between \(t = -4 \text{ s}\) and \(t = 4 \text{ s}\). This force increases from 0 N at \(t = -4 \text{ s}\) to 16 N at \(t = 0 \text{ s}\) and then back to 0 N at \(t = 4 \text{ s}\). What is the particle’s velocity at \(t = 4 \text{ s}\)?