Fundamentals of Physics 10th ISV Edition Β· Rolling, Torque, and Angular Momentum Β· Problem 45
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Halliday, Resnick & Walker β Rolling, Torque, and Angular Momentum: Problem 45
45 A man stands on a platform that is rotating (without friction) with an angular speed of 1.2 rev/s; his arms are outstretched and he holds a brick in each hand. The rotational inertia of the system consisting of the man, bricks, and platform about the central vertical axis of the platform is \(6.0 \text{ kg} \cdot \text{m}^2\). If by moving the bricks the man decreases the rotational inertia of the system to \(2.0 \text{ kg} \cdot \text{m}^2\), what are (a) the resulting angular speed of the platform and (b) the ratio of the new kinetic energy of the system to the original kinetic energy? (c) What source provided the added kinetic energy?
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Given: 45 A
Find: (a) the resulting angular speed of the platform and; (b) the ratio of the new kinetic energy of the system to the ori; (c) What source provided the added kinetic energy?
This problem covers key concepts in Rolling, Torque, and Angular Momentum from Fundamentals of Physics 10th ISV Edition by Halliday, Resnick & Walker. The step-by-step solution involves applying fundamental principles and systematic analysis to arrive at the correct answer. Full solution available with a Solution Pass.
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Fundamentals of Physics Β· 10th ISV Edition
Author: Halliday, Resnick & Walker
Publisher: Wiley
Chapter: Rolling, Torque, and Angular Momentum