Meriam, Kraige & Bolton — Kinematics of Particles: Problem 2_208

*2/208 If all frictional effects are neglected, the expression for the angular acceleration of the simple pendulum is \(\ddot{\theta} = \frac{g}{l} \cos \theta\), where \(g\) is the acceleration of gravity and \(l\) is the length of the rod \(OA\). If the pendulum has a clockwise angular velocity \(\dot{\theta} = 2 \text{ rad/s}\) when \(\theta = 0\) at \(t = 0\), determine the time \(t'\) at which the pendulum passes the vertical position \(\theta = 90^\circ\). The pendulum length is \(l = 0.6 \text{ m}\). Also plot the time \(t\) versus the angle \(\theta\).